\(\int \frac {1}{\sqrt [5]{a+b x^5} (c+d x^5)} \, dx\) [223]

Optimal result

Integrand size = 21, antiderivative size = 545 \[ \int \frac {1}{\sqrt [5]{a+b x^5} \left (c+d x^5\right )} \, dx=-\frac {\sqrt {\frac {1}{2} \left (5+\sqrt {5}\right )} \arctan \left (\sqrt {\frac {1}{5} \left (5-2 \sqrt {5}\right )}-\frac {2 \sqrt {\frac {2}{5+\sqrt {5}}} \sqrt [5]{b c-a d} x}{\sqrt [5]{c} \sqrt [5]{a+b x^5}}\right )}{5 c^{4/5} \sqrt [5]{b c-a d}}+\frac {\sqrt {\frac {1}{2} \left (5-\sqrt {5}\right )} \arctan \left (\sqrt {\frac {1}{5} \left (5+2 \sqrt {5}\right )}+\frac {\sqrt {\frac {2}{5} \left (5+\sqrt {5}\right )} \sqrt [5]{b c-a d} x}{\sqrt [5]{c} \sqrt [5]{a+b x^5}}\right )}{5 c^{4/5} \sqrt [5]{b c-a d}}-\frac {\log \left (\sqrt [5]{c}-\frac {\sqrt [5]{b c-a d} x}{\sqrt [5]{a+b x^5}}\right )}{5 c^{4/5} \sqrt [5]{b c-a d}}+\frac {\left (1-\sqrt {5}\right ) \log \left (\frac {2 (b c-a d)^{2/5} x^2+\sqrt [5]{c} \sqrt [5]{b c-a d} x \sqrt [5]{a+b x^5}-\sqrt {5} \sqrt [5]{c} \sqrt [5]{b c-a d} x \sqrt [5]{a+b x^5}+2 c^{2/5} \left (a+b x^5\right )^{2/5}}{\left (a+b x^5\right )^{2/5}}\right )}{20 c^{4/5} \sqrt [5]{b c-a d}}+\frac {\left (1+\sqrt {5}\right ) \log \left (\frac {2 (b c-a d)^{2/5} x^2+\sqrt [5]{c} \sqrt [5]{b c-a d} x \sqrt [5]{a+b x^5}+\sqrt {5} \sqrt [5]{c} \sqrt [5]{b c-a d} x \sqrt [5]{a+b x^5}+2 c^{2/5} \left (a+b x^5\right )^{2/5}}{\left (a+b x^5\right )^{2/5}}\right )}{20 c^{4/5} \sqrt [5]{b c-a d}} \]

[Out]

-1/5*ln(c^(1/5)-(-a*d+b*c)^(1/5)*x/(b*x^5+a)^(1/5))/c^(4/5)/(-a*d+b*c)^(1/5)+1/20*ln((2*(-a*d+b*c)^(2/5)*x^2+c
^(1/5)*(-a*d+b*c)^(1/5)*x*(b*x^5+a)^(1/5)+2*c^(2/5)*(b*x^5+a)^(2/5)-c^(1/5)*(-a*d+b*c)^(1/5)*x*(b*x^5+a)^(1/5)
*5^(1/2))/(b*x^5+a)^(2/5))*(-5^(1/2)+1)/c^(4/5)/(-a*d+b*c)^(1/5)+1/20*ln((2*(-a*d+b*c)^(2/5)*x^2+c^(1/5)*(-a*d
+b*c)^(1/5)*x*(b*x^5+a)^(1/5)+2*c^(2/5)*(b*x^5+a)^(2/5)+c^(1/5)*(-a*d+b*c)^(1/5)*x*(b*x^5+a)^(1/5)*5^(1/2))/(b
*x^5+a)^(2/5))*(5^(1/2)+1)/c^(4/5)/(-a*d+b*c)^(1/5)+1/10*arctan(1/5*(-a*d+b*c)^(1/5)*x*(50+10*5^(1/2))^(1/2)/c
^(1/5)/(b*x^5+a)^(1/5)+1/5*(25+10*5^(1/2))^(1/2))*(10-2*5^(1/2))^(1/2)/c^(4/5)/(-a*d+b*c)^(1/5)+1/10*arctan(-1
/5*(25-10*5^(1/2))^(1/2)+2*(-a*d+b*c)^(1/5)*x*2^(1/2)/(5+5^(1/2))^(1/2)/c^(1/5)/(b*x^5+a)^(1/5))*(10+2*5^(1/2)
)^(1/2)/c^(4/5)/(-a*d+b*c)^(1/5)

Rubi [A] (verified)

Time = 0.86 (sec) , antiderivative size = 545, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {385, 208, 648, 632, 210, 642, 31} \[ \int \frac {1}{\sqrt [5]{a+b x^5} \left (c+d x^5\right )} \, dx=-\frac {\sqrt {\frac {1}{2} \left (5+\sqrt {5}\right )} \arctan \left (\sqrt {\frac {1}{5} \left (5-2 \sqrt {5}\right )}-\frac {2 \sqrt {\frac {2}{5+\sqrt {5}}} x \sqrt [5]{b c-a d}}{\sqrt [5]{c} \sqrt [5]{a+b x^5}}\right )}{5 c^{4/5} \sqrt [5]{b c-a d}}+\frac {\sqrt {\frac {1}{2} \left (5-\sqrt {5}\right )} \arctan \left (\frac {\sqrt {\frac {2}{5} \left (5+\sqrt {5}\right )} x \sqrt [5]{b c-a d}}{\sqrt [5]{c} \sqrt [5]{a+b x^5}}+\sqrt {\frac {1}{5} \left (5+2 \sqrt {5}\right )}\right )}{5 c^{4/5} \sqrt [5]{b c-a d}}-\frac {\log \left (\sqrt [5]{c}-\frac {x \sqrt [5]{b c-a d}}{\sqrt [5]{a+b x^5}}\right )}{5 c^{4/5} \sqrt [5]{b c-a d}}+\frac {\left (1-\sqrt {5}\right ) \log \left (\frac {2 c^{2/5} \left (a+b x^5\right )^{2/5}-\sqrt {5} \sqrt [5]{c} x \sqrt [5]{a+b x^5} \sqrt [5]{b c-a d}+\sqrt [5]{c} x \sqrt [5]{a+b x^5} \sqrt [5]{b c-a d}+2 x^2 (b c-a d)^{2/5}}{\left (a+b x^5\right )^{2/5}}\right )}{20 c^{4/5} \sqrt [5]{b c-a d}}+\frac {\left (1+\sqrt {5}\right ) \log \left (\frac {2 c^{2/5} \left (a+b x^5\right )^{2/5}+\sqrt {5} \sqrt [5]{c} x \sqrt [5]{a+b x^5} \sqrt [5]{b c-a d}+\sqrt [5]{c} x \sqrt [5]{a+b x^5} \sqrt [5]{b c-a d}+2 x^2 (b c-a d)^{2/5}}{\left (a+b x^5\right )^{2/5}}\right )}{20 c^{4/5} \sqrt [5]{b c-a d}} \]

[In]

Int[1/((a + b*x^5)^(1/5)*(c + d*x^5)),x]

[Out]

-1/5*(Sqrt[(5 + Sqrt[5])/2]*ArcTan[Sqrt[(5 - 2*Sqrt[5])/5] - (2*Sqrt[2/(5 + Sqrt[5])]*(b*c - a*d)^(1/5)*x)/(c^
(1/5)*(a + b*x^5)^(1/5))])/(c^(4/5)*(b*c - a*d)^(1/5)) + (Sqrt[(5 - Sqrt[5])/2]*ArcTan[Sqrt[(5 + 2*Sqrt[5])/5]
+ (Sqrt[(2*(5 + Sqrt[5]))/5]*(b*c - a*d)^(1/5)*x)/(c^(1/5)*(a + b*x^5)^(1/5))])/(5*c^(4/5)*(b*c - a*d)^(1/5))
- Log[c^(1/5) - ((b*c - a*d)^(1/5)*x)/(a + b*x^5)^(1/5)]/(5*c^(4/5)*(b*c - a*d)^(1/5)) + ((1 - Sqrt[5])*Log[(
2*(b*c - a*d)^(2/5)*x^2 + c^(1/5)*(b*c - a*d)^(1/5)*x*(a + b*x^5)^(1/5) - Sqrt[5]*c^(1/5)*(b*c - a*d)^(1/5)*x*
(a + b*x^5)^(1/5) + 2*c^(2/5)*(a + b*x^5)^(2/5))/(a + b*x^5)^(2/5)])/(20*c^(4/5)*(b*c - a*d)^(1/5)) + ((1 + Sq
rt[5])*Log[(2*(b*c - a*d)^(2/5)*x^2 + c^(1/5)*(b*c - a*d)^(1/5)*x*(a + b*x^5)^(1/5) + Sqrt[5]*c^(1/5)*(b*c - a
*d)^(1/5)*x*(a + b*x^5)^(1/5) + 2*c^(2/5)*(a + b*x^5)^(2/5))/(a + b*x^5)^(2/5)])/(20*c^(4/5)*(b*c - a*d)^(1/5)
)

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 208

Int[((a_) + (b_.)*(x_)^(n_))^(-1), x_Symbol] :> Module[{r = Numerator[Rt[-a/b, n]], s = Denominator[Rt[-a/b, n
]], k, u}, Simp[u = Int[(r + s*Cos[(2*k - 1)*(Pi/n)]*x)/(r^2 + 2*r*s*Cos[(2*k - 1)*(Pi/n)]*x + s^2*x^2), x]; (
r/(a*n))*Int[1/(r - s*x), x] + Dist[2*(r/(a*n)), Sum[u, {k, 1, (n - 1)/2}], x], x]] /; FreeQ[{a, b}, x] && IGt
Q[(n - 3)/2, 0] && NegQ[a/b]

Rule 210

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^(-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])
], x] /; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 385

Int[((a_) + (b_.)*(x_)^(n_))^(p_)/((c_) + (d_.)*(x_)^(n_)), x_Symbol] :> Subst[Int[1/(c - (b*c - a*d)*x^n), x]
, x, x/(a + b*x^n)^(1/n)] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0] && EqQ[n*p + 1, 0] && IntegerQ[n]

Rule 632

Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> Dist[-2, Subst[Int[1/Simp[b^2 - 4*a*c - x^2, x], x]
, x, b + 2*c*x], x] /; FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 642

Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Simp[d*(Log[RemoveContent[a + b*x +
c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c*d - b*e, 0]

Rule 648

Int[((d_.) + (e_.)*(x_))/((a_) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Dist[(2*c*d - b*e)/(2*c), Int[1/(a +
b*x + c*x^2), x], x] + Dist[e/(2*c), Int[(b + 2*c*x)/(a + b*x + c*x^2), x], x] /; FreeQ[{a, b, c, d, e}, x] &
& NeQ[2*c*d - b*e, 0] && NeQ[b^2 - 4*a*c, 0] &&  !NiceSqrtQ[b^2 - 4*a*c]

Rubi steps \begin{align*} \text {integral}& = \text {Subst}\left (\int \frac {1}{c-(b c-a d) x^5} \, dx,x,\frac {x}{\sqrt [5]{a+b x^5}}\right ) \\ & = \frac {2 \text {Subst}\left (\int \frac {\sqrt [5]{c}+\frac {1}{4} \left (1-\sqrt {5}\right ) \sqrt [5]{b c-a d} x}{c^{2/5}+\frac {1}{2} \left (1-\sqrt {5}\right ) \sqrt [5]{c} \sqrt [5]{b c-a d} x+(b c-a d)^{2/5} x^2} \, dx,x,\frac {x}{\sqrt [5]{a+b x^5}}\right )}{5 c^{4/5}}+\frac {2 \text {Subst}\left (\int \frac {\sqrt [5]{c}+\frac {1}{4} \left (1+\sqrt {5}\right ) \sqrt [5]{b c-a d} x}{c^{2/5}+\frac {1}{2} \left (1+\sqrt {5}\right ) \sqrt [5]{c} \sqrt [5]{b c-a d} x+(b c-a d)^{2/5} x^2} \, dx,x,\frac {x}{\sqrt [5]{a+b x^5}}\right )}{5 c^{4/5}}+\frac {\text {Subst}\left (\int \frac {1}{\sqrt [5]{c}-\sqrt [5]{b c-a d} x} \, dx,x,\frac {x}{\sqrt [5]{a+b x^5}}\right )}{5 c^{4/5}} \\ & = -\frac {\log \left (\sqrt [5]{c}-\frac {\sqrt [5]{b c-a d} x}{\sqrt [5]{a+b x^5}}\right )}{5 c^{4/5} \sqrt [5]{b c-a d}}+\frac {\left (5-\sqrt {5}\right ) \text {Subst}\left (\int \frac {1}{c^{2/5}+\frac {1}{2} \left (1+\sqrt {5}\right ) \sqrt [5]{c} \sqrt [5]{b c-a d} x+(b c-a d)^{2/5} x^2} \, dx,x,\frac {x}{\sqrt [5]{a+b x^5}}\right )}{20 c^{3/5}}+\frac {\left (5+\sqrt {5}\right ) \text {Subst}\left (\int \frac {1}{c^{2/5}+\frac {1}{2} \left (1-\sqrt {5}\right ) \sqrt [5]{c} \sqrt [5]{b c-a d} x+(b c-a d)^{2/5} x^2} \, dx,x,\frac {x}{\sqrt [5]{a+b x^5}}\right )}{20 c^{3/5}}+\frac {\left (1-\sqrt {5}\right ) \text {Subst}\left (\int \frac {\frac {1}{2} \left (1-\sqrt {5}\right ) \sqrt [5]{c} \sqrt [5]{b c-a d}+2 (b c-a d)^{2/5} x}{c^{2/5}+\frac {1}{2} \left (1-\sqrt {5}\right ) \sqrt [5]{c} \sqrt [5]{b c-a d} x+(b c-a d)^{2/5} x^2} \, dx,x,\frac {x}{\sqrt [5]{a+b x^5}}\right )}{20 c^{4/5} \sqrt [5]{b c-a d}}+\frac {\left (1+\sqrt {5}\right ) \text {Subst}\left (\int \frac {\frac {1}{2} \left (1+\sqrt {5}\right ) \sqrt [5]{c} \sqrt [5]{b c-a d}+2 (b c-a d)^{2/5} x}{c^{2/5}+\frac {1}{2} \left (1+\sqrt {5}\right ) \sqrt [5]{c} \sqrt [5]{b c-a d} x+(b c-a d)^{2/5} x^2} \, dx,x,\frac {x}{\sqrt [5]{a+b x^5}}\right )}{20 c^{4/5} \sqrt [5]{b c-a d}} \\ & = -\frac {\log \left (\sqrt [5]{c}-\frac {\sqrt [5]{b c-a d} x}{\sqrt [5]{a+b x^5}}\right )}{5 c^{4/5} \sqrt [5]{b c-a d}}+\frac {\left (1-\sqrt {5}\right ) \log \left (2 c^{2/5}+\frac {2 (b c-a d)^{2/5} x^2}{\left (a+b x^5\right )^{2/5}}+\frac {\sqrt [5]{c} \sqrt [5]{b c-a d} x}{\sqrt [5]{a+b x^5}}-\frac {\sqrt {5} \sqrt [5]{c} \sqrt [5]{b c-a d} x}{\sqrt [5]{a+b x^5}}\right )}{20 c^{4/5} \sqrt [5]{b c-a d}}+\frac {\left (1+\sqrt {5}\right ) \log \left (2 c^{2/5}+\frac {2 (b c-a d)^{2/5} x^2}{\left (a+b x^5\right )^{2/5}}+\frac {\sqrt [5]{c} \sqrt [5]{b c-a d} x}{\sqrt [5]{a+b x^5}}+\frac {\sqrt {5} \sqrt [5]{c} \sqrt [5]{b c-a d} x}{\sqrt [5]{a+b x^5}}\right )}{20 c^{4/5} \sqrt [5]{b c-a d}}-\frac {\left (5-\sqrt {5}\right ) \text {Subst}\left (\int \frac {1}{-\frac {1}{2} \left (5-\sqrt {5}\right ) c^{2/5} (b c-a d)^{2/5}-x^2} \, dx,x,\frac {1}{2} \left (1+\sqrt {5}\right ) \sqrt [5]{c} \sqrt [5]{b c-a d}+\frac {2 (b c-a d)^{2/5} x}{\sqrt [5]{a+b x^5}}\right )}{10 c^{3/5}}-\frac {\left (5+\sqrt {5}\right ) \text {Subst}\left (\int \frac {1}{-\frac {1}{2} \left (5+\sqrt {5}\right ) c^{2/5} (b c-a d)^{2/5}-x^2} \, dx,x,\frac {1}{2} \left (1-\sqrt {5}\right ) \sqrt [5]{c} \sqrt [5]{b c-a d}+\frac {2 (b c-a d)^{2/5} x}{\sqrt [5]{a+b x^5}}\right )}{10 c^{3/5}} \\ & = \frac {\sqrt {\frac {1}{2} \left (5+\sqrt {5}\right )} \tan ^{-1}\left (\frac {\left (1-\sqrt {5}\right ) \sqrt [5]{c}+\frac {4 \sqrt [5]{b c-a d} x}{\sqrt [5]{a+b x^5}}}{\sqrt {2 \left (5+\sqrt {5}\right )} \sqrt [5]{c}}\right )}{5 c^{4/5} \sqrt [5]{b c-a d}}+\frac {\sqrt {\frac {1}{2} \left (5-\sqrt {5}\right )} \tan ^{-1}\left (\frac {\sqrt {5+\sqrt {5}} \left (\left (1+\sqrt {5}\right ) \sqrt [5]{c}+\frac {4 \sqrt [5]{b c-a d} x}{\sqrt [5]{a+b x^5}}\right )}{2 \sqrt {10} \sqrt [5]{c}}\right )}{5 c^{4/5} \sqrt [5]{b c-a d}}-\frac {\log \left (\sqrt [5]{c}-\frac {\sqrt [5]{b c-a d} x}{\sqrt [5]{a+b x^5}}\right )}{5 c^{4/5} \sqrt [5]{b c-a d}}+\frac {\left (1-\sqrt {5}\right ) \log \left (2 c^{2/5}+\frac {2 (b c-a d)^{2/5} x^2}{\left (a+b x^5\right )^{2/5}}+\frac {\sqrt [5]{c} \sqrt [5]{b c-a d} x}{\sqrt [5]{a+b x^5}}-\frac {\sqrt {5} \sqrt [5]{c} \sqrt [5]{b c-a d} x}{\sqrt [5]{a+b x^5}}\right )}{20 c^{4/5} \sqrt [5]{b c-a d}}+\frac {\left (1+\sqrt {5}\right ) \log \left (2 c^{2/5}+\frac {2 (b c-a d)^{2/5} x^2}{\left (a+b x^5\right )^{2/5}}+\frac {\sqrt [5]{c} \sqrt [5]{b c-a d} x}{\sqrt [5]{a+b x^5}}+\frac {\sqrt {5} \sqrt [5]{c} \sqrt [5]{b c-a d} x}{\sqrt [5]{a+b x^5}}\right )}{20 c^{4/5} \sqrt [5]{b c-a d}} \\ \end{align*}

Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.

Time = 10.03 (sec) , antiderivative size = 48, normalized size of antiderivative = 0.09 \[ \int \frac {1}{\sqrt [5]{a+b x^5} \left (c+d x^5\right )} \, dx=\frac {x \operatorname {Hypergeometric2F1}\left (\frac {1}{5},1,\frac {6}{5},\frac {(b c-a d) x^5}{c \left (a+b x^5\right )}\right )}{c \sqrt [5]{a+b x^5}} \]

[In]

Integrate[1/((a + b*x^5)^(1/5)*(c + d*x^5)),x]

[Out]

(x*Hypergeometric2F1[1/5, 1, 6/5, ((b*c - a*d)*x^5)/(c*(a + b*x^5))])/(c*(a + b*x^5)^(1/5))

Maple [A] (verified)

Time = 10.58 (sec) , antiderivative size = 409, normalized size of antiderivative = 0.75

method	result	size
pseudoelliptic	\(-\frac {\left (\frac {\sqrt {5+\sqrt {5}}\, \sqrt {5-\sqrt {5}}\, \left (\sqrt {5}+1\right ) \ln \left (\frac {2 \left (\frac {a d -b c}{c}\right )^{\frac {2}{5}} x^{2}-\left (\frac {a d -b c}{c}\right )^{\frac {1}{5}} \left (b \,x^{5}+a \right )^{\frac {1}{5}} \left (\sqrt {5}+1\right ) x +2 \left (b \,x^{5}+a \right )^{\frac {2}{5}}}{x^{2}}\right )}{2}-\frac {\sqrt {5+\sqrt {5}}\, \sqrt {5-\sqrt {5}}\, \left (\sqrt {5}-1\right ) \ln \left (\frac {2 \left (\frac {a d -b c}{c}\right )^{\frac {2}{5}} x^{2}+\left (\frac {a d -b c}{c}\right )^{\frac {1}{5}} \left (b \,x^{5}+a \right )^{\frac {1}{5}} \left (\sqrt {5}-1\right ) x +2 \left (b \,x^{5}+a \right )^{\frac {2}{5}}}{x^{2}}\right )}{2}+\sqrt {2}\, \sqrt {5-\sqrt {5}}\, \left (5+\sqrt {5}\right ) \arctan \left (\frac {\left (\left (\frac {a d -b c}{c}\right )^{\frac {1}{5}} \left (\sqrt {5}-1\right ) x +4 \left (b \,x^{5}+a \right )^{\frac {1}{5}}\right ) \sqrt {2}}{2 \left (\frac {a d -b c}{c}\right )^{\frac {1}{5}} \sqrt {5+\sqrt {5}}\, x}\right )+\sqrt {5+\sqrt {5}}\, \left (-2 \sqrt {5-\sqrt {5}}\, \ln \left (\frac {\left (\frac {a d -b c}{c}\right )^{\frac {1}{5}} x +\left (b \,x^{5}+a \right )^{\frac {1}{5}}}{x}\right )+\arctan \left (\frac {\sqrt {2}\, \left (\left (\frac {a d -b c}{c}\right )^{\frac {1}{5}} \left (\sqrt {5}+1\right ) x -4 \left (b \,x^{5}+a \right )^{\frac {1}{5}}\right )}{2 \left (\frac {a d -b c}{c}\right )^{\frac {1}{5}} \sqrt {5-\sqrt {5}}\, x}\right ) \sqrt {2}\, \left (\sqrt {5}-5\right )\right )\right ) \sqrt {5}}{100 \left (\frac {a d -b c}{c}\right )^{\frac {1}{5}} c}\)	\(409\)

[In]

int(1/(b*x^5+a)^(1/5)/(d*x^5+c),x,method=_RETURNVERBOSE)

[Out]

-1/100*(1/2*(5+5^(1/2))^(1/2)*(5-5^(1/2))^(1/2)*(5^(1/2)+1)*ln((2*((a*d-b*c)/c)^(2/5)*x^2-((a*d-b*c)/c)^(1/5)*
(b*x^5+a)^(1/5)*(5^(1/2)+1)*x+2*(b*x^5+a)^(2/5))/x^2)-1/2*(5+5^(1/2))^(1/2)*(5-5^(1/2))^(1/2)*(5^(1/2)-1)*ln((
2*((a*d-b*c)/c)^(2/5)*x^2+((a*d-b*c)/c)^(1/5)*(b*x^5+a)^(1/5)*(5^(1/2)-1)*x+2*(b*x^5+a)^(2/5))/x^2)+2^(1/2)*(5
-5^(1/2))^(1/2)*(5+5^(1/2))*arctan(1/2*(((a*d-b*c)/c)^(1/5)*(5^(1/2)-1)*x+4*(b*x^5+a)^(1/5))/((a*d-b*c)/c)^(1/
5)/(5+5^(1/2))^(1/2)*2^(1/2)/x)+(5+5^(1/2))^(1/2)*(-2*(5-5^(1/2))^(1/2)*ln((((a*d-b*c)/c)^(1/5)*x+(b*x^5+a)^(1
/5))/x)+arctan(1/2/((a*d-b*c)/c)^(1/5)*2^(1/2)*(((a*d-b*c)/c)^(1/5)*(5^(1/2)+1)*x-4*(b*x^5+a)^(1/5))/(5-5^(1/2
))^(1/2)/x)*2^(1/2)*(5^(1/2)-5)))*5^(1/2)/((a*d-b*c)/c)^(1/5)/c

Fricas [F(-2)]

Exception generated. \[ \int \frac {1}{\sqrt [5]{a+b x^5} \left (c+d x^5\right )} \, dx=\text {Exception raised: TypeError} \]

[In]

integrate(1/(b*x^5+a)^(1/5)/(d*x^5+c),x, algorithm="fricas")

[Out]

Exception raised: TypeError >>  Error detected within library code:   integrate: implementation incomplete (tr
ace 0)

Sympy [F]

\[ \int \frac {1}{\sqrt [5]{a+b x^5} \left (c+d x^5\right )} \, dx=\int \frac {1}{\sqrt [5]{a + b x^{5}} \left (c + d x^{5}\right )}\, dx \]

[In]

integrate(1/(b*x**5+a)**(1/5)/(d*x**5+c),x)

[Out]

Integral(1/((a + b*x**5)**(1/5)*(c + d*x**5)), x)

Maxima [F]

\[ \int \frac {1}{\sqrt [5]{a+b x^5} \left (c+d x^5\right )} \, dx=\int { \frac {1}{{\left (b x^{5} + a\right )}^{\frac {1}{5}} {\left (d x^{5} + c\right )}} \,d x } \]

[In]

integrate(1/(b*x^5+a)^(1/5)/(d*x^5+c),x, algorithm="maxima")

[Out]

integrate(1/((b*x^5 + a)^(1/5)*(d*x^5 + c)), x)

Giac [F]

\[ \int \frac {1}{\sqrt [5]{a+b x^5} \left (c+d x^5\right )} \, dx=\int { \frac {1}{{\left (b x^{5} + a\right )}^{\frac {1}{5}} {\left (d x^{5} + c\right )}} \,d x } \]

[In]

integrate(1/(b*x^5+a)^(1/5)/(d*x^5+c),x, algorithm="giac")

[Out]

integrate(1/((b*x^5 + a)^(1/5)*(d*x^5 + c)), x)

Mupad [F(-1)]

Timed out. \[ \int \frac {1}{\sqrt [5]{a+b x^5} \left (c+d x^5\right )} \, dx=\int \frac {1}{{\left (b\,x^5+a\right )}^{1/5}\,\left (d\,x^5+c\right )} \,d x \]

[In]

int(1/((a + b*x^5)^(1/5)*(c + d*x^5)),x)

[Out]

int(1/((a + b*x^5)^(1/5)*(c + d*x^5)), x)